10000000 发表于 2018-11-10 | 分类于 实验吧Writeup 先在IDA中看看程序逻辑,找到关键代码在OD中找到需要比较的字符串v4给出exp: v4 = [0xE6,0xEC,0xE1,0xE7,0xBA,0xF4,0xE5,0xF3,0xF4,0xF4,0xE5,0xF3,0xF4] v14 = [] for i in range(len(v4)): v14.append(v4[i]-0x80) # 或运算的逆运算是减法 flag = '' for i in v14: flag += chr(i) print flag