10000000

先在IDA中看看程序逻辑,找到关键代码
图1
在OD中找到需要比较的字符串v4
图2
给出exp:

v4 = [0xE6,0xEC,0xE1,0xE7,0xBA,0xF4,0xE5,0xF3,0xF4,0xF4,0xE5,0xF3,0xF4]
v14 = []
for i in range(len(v4)):
  v14.append(v4[i]-0x80)  # 或运算的逆运算是减法
flag = ''
for i in v14:
  flag += chr(i)
print flag